| Subject: ?Could sort+ be quicker than for-each not preceding From: "davidpbrown" <lists@xxxxxxxxxxxxxxxxx> Date: Fri, 18 Jun 2004 15:36:39 +0100 | 
I'm expecting this has been thought of but then couldn't find mention of it.. For large <for-each not preceding> would it be quicker to do sort list when current-node not equal to immediately-preceding-sibling then DO otherwise look for the next following-sibling not equal to current-node ? I don't know if internally Saxon already does something similar to this. Or is finding immediate siblings costly? If this works, I'm wondering when it becomes worthwhile? Regards davidpbrown
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