| Subject: Fwd: [exslt] param problem From: xptm@xxxxxxx Date: Fri, 2 Jul 2004 12:04:26 +0100 | 
Hello:
Please forgive me for posting this in this list, but i got no answer from the
[exslt] list so i think maybe in here can help.
Hello:
I have a xsl using exslt.org/functions
<?xml version="1.0" encoding="ISO8859-1" ?>
<xsl:stylesheet version="2.0"
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:func="http://exslt.org/functions"
    xmlns:gti="http://www.gtinformatica.pt">
  <func:function name="gti:facton">
    <xsl:param name="val"/>
    <func:result select="round($val div 14)"/>
  </func:function>
</xsl:stylesheet>
wich i'm importing into another
<?xml version="1.0" encoding="ISO8859-1" ?>
<xsl:transform version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:output method="xml" version="1.0" encoding="iso-8859-1"
indent="yes"/>
  <!-- Funções -->
  <xsl:include href="xfunctions.xsl" />
  (...more stuff...)
No i want to pass a parameter from a Java program to this XSLT, so i have
<?xml version="1.0" encoding="ISO8859-1" ?>
<xsl:transform version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:output method="xml" version="1.0" encoding="iso-8859-1"
indent="yes"/>
 <xsl:param name="sqlvars" select="'default'" />
  <!-- Funções -->
  <xsl:include href="xfunctions.xsl" />
  (...more stuff...)
but i allways get this error:
javax.xml.transform.TransformerException:
javax.xml.transform.TransformerException: An EXSLT function cannot set
more than one result!
What is going on? I use Xalan Java 2.4.1
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