RE: [xsl] finding position in list of siblings

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Subject: RE: [xsl] finding position in list of siblings
From: cknell@xxxxxxxxxx
Date: Fri, 09 Jul 2004 15:13:00 -0400

Try this template:

<xsl:template match="BROTHER">
   <xsl:value-of select="count(preceding-sibling::*[name()='BROTHER')" />
</xsl:template>

--
Charles Knell
cknell@xxxxxxxxxx - email

Current Thread
[xsl] finding position in list of siblings John C Cartwright - Fri, 09 Jul 2004 12:56:57 -0600 Wendell Piez - Fri, 09 Jul 2004 15:57:58 -0400 David Carlisle - Sat, 10 Jul 2004 17:13:48 +0100 <Possible follow-ups> cknell - Fri, 09 Jul 2004 15:13:00 -0400 <= John C Cartwright - Fri, 09 Jul 2004 13:29:36 -0600 cknell - Fri, 09 Jul 2004 16:31:52 -0400

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