Subject: RE: [xsl] Curious result of the position() function From: "Michael Kay" <mhk@xxxxxxxxx> Date: Sun, 1 Aug 2004 19:38:53 +0100 |
> I believed that the position() function should give me the > position number > of the node in the node set. But it appears to not being the > case. I don't > understand the result of this function (I use saxon to > process my xsl > transformation). It numbers my row nodes 2 by 2. > Can somebody explain me what I missed ? > In case you didn't get the message from previous answers, you have selected a node sequence that contains element nodes alternating with whitespace-only text nodes. Therefore, the element nodes are all in even-numbered positions. Consider using xsl:strip-space to get rid of the whitespace-only text nodes. Michael Kay
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