[xsl] Position() with absolute paths

["Jeff Cann" <Jeff.Cann@xxxxxxxxxxxxxxx>]

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Hi,

I was wondering how to find the number of elements with a certain path that
precede the current element. For example, I have the document:

<a>
  <b>
    <c>
      <e attr="345" />
      <d attr="xyz">
        <e x="1"/>
        <e x="2"/>
        <e x="3"/>
      </d>
      <d attr="xyz">
        <e x="4"/>
        <e x="5"/>
        <e x="6"/>
      </d>
    </c>
    <c>
      <e attr="123" />
      <d attr="abc">
        <e x="7"/>
        <e x="8"/>
        <e x="9"/>
      </d>
      <d attr="xyz">
        <e x="10"/>
        <e x="11"/>
        <e x="12"/>
      </d>
    </c>
  </b>
</a>

Say the current node is /a/b/c/d/e (where @x="8"), how do I find the number of
/a/b/c/d/e elements (not just the number of 'e' elements) that precede the
current node? The reason I need to use the full path is because this is for a
generic paging stylesheet, where the full path is passed in as an arguement.
I have been trying to use count(preceding:://a/b/c/d/e), but this is invalid.
Any help greatly appreciated!

Thanks,
Jeff.



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