Subject: RE: [xsl] Getting a unique list - one more try at emailing this From: "Michael Kay" <mhk@xxxxxxxxx> Date: Sat, 7 Aug 2004 00:34:04 +0100 |
> I'd like to know how to print a unique list of states from > the data set > below. Thanks in advance. Getting distinct values is a special case of grouping: see http://www.jenitennison.com/xslt/grouping Michael Kay > > A newbie. > > <data> > <level name = "starter"> > <process name = "TR"> > <state name = "NY">143</state> > <state name = "CA">19</state> > <state name = "FL">215</state> > </process> > <process name = "PD"> > <state name = "NY">61</state> > <state name = "CA">721</state> > <state name = "FL">518</state> > </process> > </level> > <level name = "mediumr"> > <process name = "TR"> > <state name = "NY">709</state> > <state name = "CA"1285</state> > <state name = "FL">52</state> > </process> > <process name = "YF"> > <state name = "NY">8</state> > <state name = "CA">0</state> > <state name = "FL">9</state> > </process> > </level> > </data> > > _________________________________________________________________ > Check out Election 2004 for up-to-date election news, plus > voter tools and > more! http://special.msn.com/msn/election2004.armx
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