RE: [xsl] Getting a unique list - one more try at emailing this

Subject: RE: [xsl] Getting a unique list - one more try at emailing this
From: "Michael Kay" <mhk@xxxxxxxxx>
Date: Sat, 7 Aug 2004 00:34:04 +0100
> I'd like to know how to print a unique list of states from 
> the data set 
> below.  Thanks in advance.

Getting distinct values is a special case of grouping: see
http://www.jenitennison.com/xslt/grouping

Michael Kay


> 
> A newbie.
> 
> <data>
> <level name = "starter">
>     <process name = "TR">
>        <state name = "NY">143</state>
>        <state name = "CA">19</state>
>        <state name = "FL">215</state>
>     </process>
>     <process name = "PD">
>        <state name = "NY">61</state>
>        <state name = "CA">721</state>
>        <state name = "FL">518</state>
>     </process>
> </level>
> <level name = "mediumr">
>     <process name = "TR">
>        <state name = "NY">709</state>
>        <state name = "CA"1285</state>
>        <state name = "FL">52</state>
>     </process>
>     <process name = "YF">
>        <state name = "NY">8</state>
>        <state name = "CA">0</state>
>        <state name = "FL">9</state>
>     </process>
> </level>
> </data>
> 
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