Re: [xsl] Omit Data While Using Copy

[Josh Canfield <joshcanfield@xxxxxxxxx>]

Here is a good start:
http://www.dpawson.co.uk/xsl/sect2/N1930.html#d2955e100

basically it is a modified identity transform.

On Wed, 11 Aug 2004 13:57:39 -0500, Trevor Majic <majic87@xxxxxxxxxxx> wrote:
> How would I be able to display all of the data from the following xml file,
> EXCEPT for the <titel> text? (see xml example below  which is one of 1200)
>
> <?xml version="1.0"?><?xml:stylesheet type='text/xsl' href='manual.xsl'?>
> <kapitel><titel>Measures every 10 percussion
hours</titel><text/><hanvisning
> from="ID(SEUHS-SLAGVT-10-MATARE13)">Feeder</hanvisning><text/><hanvisning
>
from="ID(SEUHS-SLAGVT-10-BOM19)">Boom</hanvisning><text/><hanvisning></kapite
l>
>
> I can use xsl:copy and select=node() to display everything, but no matter
> what I try, I can't seem to keep the <titel> from displaying.  If I try to
> just use match, I am only able to display "Feeder".
>
> This is the basic xsl I was working from:
>
> <?xml version='1.0' encoding='utf-8' ?>
> <xsl:stylesheet version="1.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
>  <xsl:template match="kapitel/hanvisning">
>     <xsl:copy>
>        <xsl:value-of select="node()"/>
>     </xsl:copy>
>  </xsl:template>
> </xsl:stylesheet>
>
> If you respond to this, please be fairly descriptive, as I am very new to
> xsl.
>
> Thanks in advance,
> Trevor
>
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