Re: [xsl] using traslate function to replace strings

<-prev [Thread] next->	<-prev [Date] next->
Month Index \| List Home

Re: [xsl] using traslate function to replace strings

Subject: Re: [xsl] using traslate function to replace strings
From: kotes mog <kotesm@xxxxxxxxx>
Date: Fri, 13 Aug 2004 12:11:40 -0700 (PDT)

Marina,

Thanks for the help. The "replace-string" template
available in FAQ has solved the problem.

Thanks
Kotes

--- Marina Cuello <cuello@xxxxxxxxxxxxxx> wrote:

> >                 <xsl:value-of
> select="concat($cutA,'dependency'.$cutB)"/>
> 
> I'm sorry, it's "concat($cutA,'dependency',$cutB)"
>           
> Marina
> 
> 

__________________________________
Do you Yahoo!?
New and Improved Yahoo! Mail - 100MB free storage!
http://promotions.yahoo.com/new_mail

Current Thread
RE: [xsl] file_size_affecting_transformation??:manpreet, (continued) Suman Kumar - Thu, 5 Aug 2004 16:35:24 +0530 kotes mog - Fri, 6 Aug 2004 14:36:17 -0700 (PDT) Marina Cuello - Fri, 6 Aug 2004 19:16:56 -0300 Marina Cuello - Fri, 6 Aug 2004 19:20:09 -0300 kotes mog - Fri, 13 Aug 2004 12:11:40 -0700 (PDT) <= Michael Kay - Sat, 7 Aug 2004 00:33:05 +0100

<- Previous	Index	Next ->
Re: [xsl] using traslate function t, Marina Cuello	Thread	RE: [xsl] using traslate function t, Michael Kay
RE: [xsl] using traslate function t, kotes mog	Date	Re: [xsl] grouping + global variabl, Wendell Piez
	Month