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Subject: [xsl] Dynamically generating lists of finite length From: Brendan Moran <bmoran@xxxxxxxxx> Date: Fri, 13 Aug 2004 15:48:07 -0700 |
Hi,
I'm using xsl to generate a series of pages dynamically from a
database. I want to produce pages with a finite number of records
(say 100) out of a 3 level tree,
<a>
<b>
<c>1</c>
<c>2</c>
<c>3</c>
<c>4</c>
</b>
<b>
<c>1</c>
<c>2</c>
<c>3</c>
<c>4</c>
<c>5</c>
<c>6</c>
</b>
<!--(etc. etc. etc.)-->
</a>Some attributes of 'b' elements need to be displayed at the start of a 'b' section or at the start of a page if a 'b' section is split across pages. Only 'c' elements count towards the 100 elements per page. And I need to generate a link to the next page (just <a heref="javascript:foo(param1,param2,param3...);">) and the previous page. Preferably at top and bottom.
The number of c elements in any given b element is unknown, and has no practical limit. There may be b elements that contain no c elements. Naturally, information for those b elements should not be displayed.
I've been trying to figure this one out for a while now, but I'm lost on it.
Thanks --
Brendan Moran Research & Development http://www.tri-m.com
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