RE: [xsl] xslt regex escaping

[David.Pawson@xxxxxxxxxxx]

Solution.
Note the mixed "'" in the regex attribute.

Thanks DC.
regards DaveP

src =
<l>components['kdemultimedia'] = "Multimedia applications for the K Desktop
Environment (KDE).";</l>
<l>components['m4'] = "The GNU macro processor.";</l>

 <xsl:template match="l">
    <p> src: <i>   <xsl:value-of select="."/></i></p>
    <p>
<!-- escaping -->
<xsl:analyze-string
  select="."
  regex="components\['([a-z0-9]+)'\] = &#x0022;([^&#x0022;]+)&#x0022;">
  <xsl:matching-substring>
1   <xsl:value-of select="regex-group(1)"/> <br />
2    <xsl:value-of select="regex-group(2)"/>

  </xsl:matching-substring>
  <xsl:non-matching-substring>

Mismatch:    <xsl:value-of select="."/>
  </xsl:non-matching-substring>
</xsl:analyze-string>
</p>

  </xsl:template>

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