Re: [xsl] Calling templates based on node contents

[David Carlisle <davidc@xxxxxxxxx>]

> Unfortunatly I get the same result with your template as I did with mine.

It's rather hard to debug since you still have not really shown either
your input or desired output or what rules you are wanting to apply to
get from one to the other.

I suggested:
	
<xsl:template match="contentField">
 <a class="{concat(contentFieldElement, '_', contentFieldStyle)}" 

and you say you got

<a class="defaultField_default" href="Default url text -- please update">Default text -- please update</a>
<a class="defaultField_A" href="Default url text -- please update">Default text -- please update</a>

So I assume that some of your input had a contentFieldStyle of A
(although the sample you posted did not)

  ideally the output should look like:
  <span class="defaultField_default">Default text -- please update</span>
  <a class="defaultField_A" href="Default url text -- please update">Default text -- please update</a>

again you haven't given any indication of what rules you want to apply
that would give that output, I could guess some rules such as

if there is a contentItemValue[@type='url'] make an <a href=> otherwise
make a <span>

in which case you need two templates, such as:


<xsl:template match="contentField[contentFieldValue/contentItem/contentItemValue[@type='url']]">
 <a class="{concat(contentFieldElement, '_', contentFieldStyle)}" 
    href="{contentFieldValue/contentItem/contentItemValue[@type='url']}">
   <xsl:value-of select="contentFieldValue/contentItem/contentItemValue[@type='text']"/>
</a>
</xsl:template>

<xsl:template match="contentField">
 <span class="{concat(contentFieldElement, '_', contentFieldStyle)}">
   <xsl:value-of select="contentFieldValue/contentItem/contentItemValue[@type='text']"/>
</span>
</xsl:template>

But there could be any number of other rules that you have in mind that
would lead to your desired output.


David

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