Re: [xsl] Simple list -> Nested list based on attribute values

[Josh Canfield <joshcanfield@xxxxxxxxx>]

this faq page should help.
http://www.dpawson.co.uk/xsl/sect2/flatfile.html#d4548e117

Josh

On Thu, 19 Aug 2004 18:48:42 +0200, jhaines@xxxxxxxxxxxxxxxxxx
<jhaines@xxxxxxxxxxxxxxxxxx> wrote:
> I have an XML document of the form
> 
> <doc>
>  <item header='true'>Section 1</item>
>  <item>Section 1.1</item>
>  <item>Section 1.2</item>
> 
>  <item header='true'>Section 2</item>
>  <item>Section 2.1</item>
>  <item>Section 2.2</item>
> </doc>
> 
> that I want to transform to the following:
> 
> <doc>
>  <section title="Section 1">
>    <item>Section 1.1</item>
>    <item>Section 1.2</item>
>  </section>
> 
>  <section title="Section 2">
>    <item>Section 2.1</item>
>    <item>Section 2.2</item>
>  </section>
> </doc>
> 
> I was able to match the @header <item>s with the rule 'item[@header =
> "true"]' but couldn't work out a predicate to match "all subsequent
> <item>s up until the next @header <item>".
> 
> Jason
> 
> Any information in this communication is confidential and may be privileged or otherwise protected from disclosure without our consent. If you are not the intended recipient, you are not authorised to and must not disclose, copy, distribute, or retain this message or any part of it. You are requested to please telephone or email the sender and delete this message and any attachment from your system.
> 
> Due to the electronic nature of e-mail, there is a risk that the information contained in this message has been modified. Consequently we can accept no responsibility or liability as to the completeness or accuracy of the information.
> 
> A-03-03-E