RE: [xsl] Printing a value if an attribute does not exist

["Vasu Chakkera" <vasucv@xxxxxxxxxxx>]

Try:

<xsl:choose>
 <xsl:when test="REGION [@NAME='VA']">
    <xsl:value-of select="REGION [@NAME='VA']"/>
 </xsl:when>
 <xsl:otherwise>0.0</xsl:otherwise>
</xsl:choose>



> From: michael.s.eberhart@xxxxxxxxxxx
> Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] Printing a value if an attribute does not exist
> Date: Mon, 23 Aug 2004 23:04:11 -0400
>
>
>
>
>
> How do you check for the existence of an attribute?
>
> <TIER>
>    <REGION NAME="CT">89</REGION>
>    <REGION NAME="MD">135</REGION>
> </TIER>
>
> What I want to say is:
>
> If region[@name="VA"] exists
>    print value of region[@name="VA"]
> else
>    print "0.0"
>
> It is also possible that there will be no REGION elements
>
> <TIER>
> </TIER>
>
> I would still want to say:
>
> If region[@name="VA"] exists
>    print value of region[@name="VA"]
> else
>    print "0.0"
>
> Thanks
>
> Mike

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