Subject: RE: [xsl] Finding the following sibling of same type From: "Michael Kay" <mhk@xxxxxxxxx> Date: Sun, 29 Aug 2004 23:59:50 +0100 |
> If I am on the first "first" element node, how can I write an > XPath expression to get the position of the second instance of the > "first" element? I can write > > followin-sibling::first[position() = 1] > > ....to locate the element, but I'm having trouble figuring out how to > find its position within the parent (main). count(following-sibling::first[1]/preceding-sibling::*)+1 > > Actually, the real problem is for me to write an XPath expression > that will select all children of "main" from the first "first" upto > (but exluding) the next "first". <xsl:variable name="first-first" select="first[1]"/> <xsl:... select="$first-first/following-sibling::*[ preceding-sibling::first[1] is $first-first]"/> "is" is an XPath 2.0 operator to test node-identity; in XPath 1.0 replace "A is B" by "generate-id(A) = generate-id(B)". Michael Kay
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