Re: [xsl] xhtml xslt?

["Jeffrey Moss" <jeff@xxxxxxxxxxxx>]

I had the same problem, I use this:

  <xsl:template match="*">
    <xsl:element name="{name(.)}">
      <xsl:for-each select="@*">
        <xsl:attribute name="{name(.)}">
          <xsl:value-of select="."/>
        </xsl:attribute>
      </xsl:for-each>
      <xsl:apply-templates/>
    </xsl:element>
  </xsl:template>

-Jeff Moss

----- Original Message ----- 
From: "Nathan Shaw" <n8_shaw@xxxxxxxxx>
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Monday, August 30, 2004 11:55 AM
Subject: Re: [xsl] xhtml xslt?


> OK, this works, but it is copying the namespace along
> with the elements. My output from this transformation
> should be XHTML, so I need to drop the namespace so
> that I do not end up with xhtml:strong, etc...
> 
> How can I do a copy but drop the namespace?
> 
> Thanks,
> 
> --Nathan
> 
> 
> 
> Date: Thu, 26 Aug 2004 10:05:34 +0100
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> From: David Carlisle <davidc@xxxxxxxxx>
> CC: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: Re: [xsl] xhtml xslt?
> Message-Id: <200408260905.KAA05731@xxxxxxxxxxxxxxxxx>
> 
> >I started to create an XSLT to accomplish this:
> 
> you just want to copy the html you don't need a
> template for each
> element, the whole point of namespaces id to make this
> easy, you can
> grab them all at once.
> 
> <xsl:template match="h:*">
> <xsl:copy>
> <xsl:copy-of select="@*"/>
> <xsl;apply-templates/>
> </xsl:copy>
> </xsl:template>
> 
> David
> 
> 
> 
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