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Subject: Re: [xsl] Re: [xslt transform & grouping] Using the Muenchian  Method? From: David Carlisle <davidc@xxxxxxxxx> Date: Thu, 7 Oct 2004 15:57:09 +0100  | 
  How can I implement filtering for two keywords, that is display all that 
  have either "food" or "drink".
as I said. you need to make $info have a node set consisting of nodes
with values
 food and drink
You may be able to pass in a node set directly from your API
(you can in msxml, passing in a dom node list if I recall)
Otherwise you'll have to generate the nodeset from a result tree
fragment or an external document inside a stylesheet you could do it
using xx:node-set or document('') eg
<xsl:variable name="info">
<x>food</x>
<x>drink</x>
</xsl:variable>
<xsl:variable name="info-nodeset"
select="document('')/*/xsl:variable[@name='info']"/>
then $info-nodeset is a node set of two nodes with values food and drink
and
@filter=$info-nodeset
will therefore be true if filter attribute is food or drink and false
otherwise.
David
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