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Subject: Re: [xsl] Variables and command line params From: xptm@xxxxxxx Date: Tue, 9 Nov 2004 12:02:36 +0000 |
How about
<xsl:variable name="list2" select="doc('$filename')//supp"/>
Citando Kevin Bird <kevin.bird@xxxxxxxxxxxxxxxxxxxxxxx>:
> Hi
>
> I want to pass a second filename as a parameter from the command line.
>
>
> The below variable declaration works in my stylesheet when the filename
> is hardcoded.
>
> <xsl:variable name="list2" select="doc('filename.xml')//supp"/>
>
> But when I change to...
>
> <xsl:variable name="list2" select="doc($filename)//supp"/>
>
> ...and add
>
> filename="filename.xml"
>
> to the command line option, I get an error - $filename has not been
> declared.
>
> Can someone please point out what I am doing wrong.
>
> Thanks.
>
> --
> Kevin
>
>
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