Subject: RE: [xsl] XSL to create nested list items? From: <Jarno.Elovirta@xxxxxxxxx> Date: Fri, 19 Nov 2004 13:27:27 +0200 |
Hi, > I tried your template sample, but kept getting errors on the first > xsl:template line. Was the xsl:template the first element in the file? You have to use xsl:stylesheet as the root element, I just omitted it for brevity. > That's PHP for you though, it's VERY > picky I'm finding, > and I don't see anything in the line that would trigger an error. > > I did manage to resolve the problem though. I took my clue > from your "menu" > template, and kicked myself for not seeing the simpler way > sooner. Instead > of simply putting a new <item> element inside an existing > one, I wrapped the > sub-menu items in a <menu> element. Then, with the XSL, I > could write a > template for the <menu> elements that would create the <ul> > tags... er, > here's the new xsl - I think it's easier to see what I did > than me trying to > explain it: > > <xsl:stylesheet version="1.0" > xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> > > <xsl:template match="/"> > <xsl:apply-templates/> > </xsl:template> > > <xsl:template match="menu"> > <ul> > <xsl:apply-templates/> > </ul> > </xsl:template> > > <xsl:template match="item"> > <li> > <a href="{url}"> > <xsl:value-of select="name"/> > </a> > </li> > <xsl:apply-templates select="menu"/> This xsl:apply-templates should be inside the above li element, right after the a element. That way you get valid XHTML. Cheers, Jarno
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