Subject: RE: [xsl] xsl key related From: "Thomas Vanparys" <thomas.vanparys@xxxxxxxxxx> Date: Sat, 20 Nov 2004 10:33:22 +0100 |
Hi Mark, Perhaps the following archive is usefull to you: http://www.biglist.com/lists/xsl-list/archives/200101/msg00202.html It's a reply Jeni Tennison gave to solve a calendar layout problem. Might be useful. Rgds, Thomas Vanparys -----Original Message----- From: Mark Ivs [mailto:markivs2003@xxxxxxxxx] Sent: 20 November 2004 02:25 To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: Re: [xsl] xsl key related Can someone give me a clue about how I can achieve the results that I have described below? Thanks again. I really appreciate your help. --- Mark Ivs <markivs2003@xxxxxxxxx> wrote: > Hello, > I would like to get a list of all unique > country_groups which has a year=2004 and num=2 and > display them in multiple table columns. So, if my > result has 10 items, then for a 2 column layout, my > table will be 2 column and 5 rows. For 3 column > layout, my table will be 3 column and 4 rows(last > column will have 2 rows filled). The number of > columns > is declared in a variable. With Jarno's help, I was > able to get the unique country_groups, but I am not > sure how to display them in multiple columns. The > xsl > currently displays all the items in one column. > > If the xsl:key contains only the unique > contry_groups > it will be earlier to accomplish what I want. But I > am > not if I that's possible. > > Can someone help please ? Thank you very much in > advance. > > Mark > > ----------------------------------- > XML - stripped down version of the original > ----------------------------------- > <?xml version="1.0"?> > <myroot> > > <country year="2004" num="1"> > <country_group>WWW</course_group> > <num>001</num> > </country> > > <country year="2004" num="1"> > <country_group>ZZZ</course_group> > <num>001</num> > </country> > > <country year="2004" num="2"> > <country_group>AAA</course_group> > <num>221</num> > </country> > > <country year="2004" num="2"> > <country_group>BBB</course_group> > <num>002</num> > </country> > > <country year="2004" num="2"> > <country_group>CCC</course_group> > <num>022</num> > </country> > > > <country year="2004" num="2"> > <country_group>AAA</course_group> > <num>011</num> > </country> > > </myroot> > > > ----------------------- > XSL > ----------------------- > <xsl:key name="groups" match="country" > use="concat(country_group, @year, @num)"/> > <xsl:variable name="numberOfColumns" select="2"/> > > <xsl:template match="myroot"> > <xsl:apply-templates select="country"> > <xsl:sort select="country_group" /> > </xsl:apply-templates> > </xsl:template> > > <xsl:template match="country"> > <xsl:if test="generate-id() = > generate-id(key('groups', concat(country_group, > '2004', '2')))"> > <tr><td><xsl:value-of > select="country_group"/></td></tr> > </xsl:if> > </xsl:template> > > > > __________________________________ > Do you Yahoo!? > Meet the all-new My Yahoo! - Try it today! > http://my.yahoo.com > > __________________________________ Do you Yahoo!? The all-new My Yahoo! - Get yours free! http://my.yahoo.com
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