Subject: RE: [xsl] Counting in several levels From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Fri, 26 Nov 2004 10:47:56 -0000 |
Instead of "parameter", which is short for "child::parameter", you need "descendant::parameter", or ".//parameter" (which in this case returns the same as "descendant::parameter"). Michael Kay http://www.saxonica.com/ > -----Original Message----- > From: Sven Waibel [mailto:sven.waibel@xxxxxxxx] > Sent: 26 November 2004 10:37 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: [xsl] Counting in several levels > > Hi, > > a new problem: > > XML: > ------------------------------------------- > <case> > <parameter> > <status value="performed"/> > <verdict value="fail"/> > </parameter> > <parameter> > status value="performed"/> > <verdict value="pass"/> > </parameter> > <parameter> > status value="performed"/> > <verdict value="pass"/> > </parameter> > <case> > <parameter> > <status value="performed"/> > <verdict value="fail"/> > </parameter> > <parameter> > status value="performed"/> > <verdict value="pass"/> > </parameter> > <parameter> > status value="performed"/> > <verdict value="pass"/> > </parameter> > </case> > </case> > > > If the current node "case" is the inner node then this is working: > <xsl:value-of > select="count(parameter[status/@value='performed' and > verdict/@value='pass'])" /> > But if my current node is the outer node, it's not working > for known reasons. > > I wanna get all parameters that "performed" and "pass". > > To make it more complex: I don't know how many nodes "case" > are in the node "case": //case/case*/parameter > > Thanks again and best regards > Sven
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