[xsl] First entry in a nodelist via Sablotron

[Cas Tuyn <Cas.Tuyn@xxxxxxxx>]

Hi,

I use the Sablotron XSLT engine inside Perl, and need to retrieve the 
first node of a nodeset.

My XML:

<history>
   <changesummary changetype="major">
     <who>guido</who>
     <what>(not specified)</what>
     <why>New section</why>
   </changesummary>
   <changesummary changetype="config">
     <who>cas</who>
     <what>(not specified)</what>
     <why>(not specified)</why>
   </changesummary>
   <changesummary changetype="config">
     <who>martijn</who>
     <what>(not specified)</what>
     <why>(not specified)</why>
   </changesummary>
</history>

My Perl:

       $root   = $tree->getDocumentElement;
       $ptitle = $root->find('title');
       $status = $root->findvalue('@status');
       $author = $root->find('history/changesummary/who');
       print "Procedure $ptitle has status $status, ";
       print "and is last changed by $author.";

My HTML output:

Procedure CALIBRATE THE PRESSURE has status RELEASED and
is last changed by guidocasmartijn

My Problem:

If there is only one node this goes OK, but for multiple nodes I pick up 
the whole nodeset. I already thried to put () around it and [0] behind 
to get the first entry of the array, but it's not an array.

Please keep the answers within the chosen tooling, I already know 
Sablotron users are a minority ;-) (but a happy minority).

Regards,

Cas


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