Re: [xsl] how to set the pattern to get the node

[Geert Josten <Geert.Josten@xxxxxxxxxxx>]

Hi Que Li,

> How I can get the node which parent_ID =1 or parent_ID
> is not 1 but No other sibling node List_ID equal to
> current node parent_ID
>
> I try to use:
>    <xsl:template match="List[Parent_ID=1 or
> not(../List[List_ID = current()/Parent_ID])] ">

The value of current() changes during the evaluation of a Path in an XPath expression. It is not 
pointing to the List element for which the math pattern is being tested.

Besides, you might want to rule out the List element under consideration from the test on the siblings..

You could try the following:

<xsl:template match="List">
  <xsl:variable name="self" select="."/> <!-- current() can be shortened to . -->
  <xsl:choose>
    <xsl:when test="Parent_ID = 1">
      <!-- found a valid case -->
    </xsl:when>
    <xsl:when test="not(preceding-sibling::List[List_ID = $self/@Parent_ID]
                        or following-sibling::List[List_ID = $self/@Parent_ID])">
      <!-- found second valid case -->
    </xsl:when>
    <!-- xsl:otherwise? -->
  </xsl:choose>
</xsl:template>

Cheers,
Geert