RE: [xsl] Tree from directory listing

["Michael Kay" <mike@xxxxxxxxxxxx>]

It's essentially a recursive grouping problem. (Yes, I have seen these
before!) In XSLT 2.0 you can solve it like this:

<xsl:template name="g">
  <xsl:param name="files" as="element(file)*"/>
  <xsl:param name="level" as="xs:integer"/>
  <xsl:for-each-group select="$files"
     group-adjacent="tokenize(@path, '/')[$level]">
   <folder name="current-grouping-key()">
     <xsl:call-template name="g">
       <xsl:with-param name="files" select="current-group() except ."/>
       <xsl:with-param name="level" select="$level + 1"/>
     </xsl:call-template>
   </folder>
  </xsl:for-each-group>
</xsl:template>

I haven't tried to distinguish folders from files here, I leave that as an
exercise for the reader (perhaps best done in a second pass).

A 1.0 solution is beyond my concentration powers at this time on a Friday
evening.

Michael Kay
http://www.saxonica.com/

> -----Original Message-----
> From: Thomas Zvchling [mailto:thomas.zoechling@xxxxxx]
> Sent: 10 December 2004 17:04
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] Tree from directory listing
>
> Hi list!
>
> Does someone know a method to create a nested xml Tree
> structure from file
> listing with paths?
>
> eg.
> ...
> <file name ="f1.xyz" path="/test/"/>
> <file name ="f2.xyz" path="/test/folderInFolder/"/>
> <file name ="f3.xyz" path="/test/folderInFolder/"/>
> <file name ="f4.xyz" path="/test/folderInFolder2/"/>
> <file name ="f5.xyz" path="/test2/folderInFolder3/"/>
> ...
>
> to
>
> <folder name="test">
>     <folder name="folderInFolder">
>         <file name="f2.xyz"/>
>         <file name="f3.xyz"/>
>     </folder
>     <folder name="folderInFolder2">
>         <file name="f4.xyz"/>
>     </folder
> <folder name ="test">
>     <folder name="folderInFolder3">
>         <file name="f5.xyz">
>     </folder>
> </folder>
>
> Maybe anyone solved a similar problem?