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Subject: [xsl] Counting sub-nodes per page in xsl with custom paging From: Anthony DiSalvo <ajdisalvo@xxxxxxxxx> Date: Fri, 10 Dec 2004 12:09:52 -0800 (PST) |
Hey everyone,
This is the first time that I am posting to the xsl list and I am
pretty new to xsl.
I would appreciate any help that you can provide with an issue I am
having.
I am generating a potentially multi-page html document.
I have the issue of repeating the header and footer worked out.
I can only display a certain number, (15), of sample nodes per page,
so when the sample node position/ 15 is greater than 1, 2, etc. I
insert the header again. Example xml and xsl is below.
<sample>
<container></container>
<container></container>
<container></container>
<container></container>
</sample>
<sample>
<container></container>
<container></container>
</sample>
<sample>
<container></container>
</sample>
<sample>
<container></container>
<container></container>
<container></container>
</sample>
<xsl:template name="pageNumber">
<xsl:choose>
<xsl:when test="position() mod
15 =0">
<xsl:value-ofselect="round(position() div 15 + 1)"/>
</xsl:when>
<xsl:otherwise>
<xsl:value-of
select="round(position() div 15 + 1)"/>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
I have been able to generate a page number such as "page 1 of 2",also
using this technique.
The problem I have not been able to figure out that I want to count
and display how many container nodes exist on a specific page, for
example "# of containers for this page = 25".
Any ideas on how I might do this?
Thanks,
Tony DiSalvo
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