Re: [xsl] Xsl copy nodes

[Geert Josten <Geert.Josten@xxxxxxxxxxx>]

<xsl:template match"@*|node()">
  <xsl:copy>
    <xsl:apply-templates select="@*|node()"/>
  </xls:copy>
</xsl:template>

<xsl:template match="STORYLIST" />

Ravi wrote:

>  Hi,
>  I'm new to xsl.
>  I have the following xml
>   <CLUSTERLIST>
>      <CLUSTER>
> 	  <STORY ID="1">
> 	  <CLUSTER>
>         	<STORY ID="2">
> 	  </CLUSTER>
>      </CLUSTER>
>      <STORYLIST>
> 	  <STORY ID="1" ATT1="att1" ATT2="att2"/>
>         <STORY ID="2" ATT1="att1" ATT2="att2"/>
>      </STORYLIST>
>   </CLUSTERLIST>
>
>
> The output I want is
>   <CLUSTERLIST>
>      <CLUSTER>
> 	  <STORY ID="1" ATT1="att1" ATT2="att2"/>
>         <CLUSTER>
> 		<STORY ID="2" ATT1="att1" ATT2="att2"/>
>         </CLUSTER>
>      </CLUSTER>
>   </CLUSTERLIST>
>
>  So I just want to move the story nodes from the story list to the
> corresponding positions (by matching the ids) under cluster nodes 
>
> Thanks in advance,
> Ravi.

--
Geert.Josten@xxxxxxxxxxx
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