RE: [xsl] xsl:sort not working under unix???

Subject: RE: [xsl] xsl:sort not working under unix???
From: "Hardy Merrill" <HMerrill@xxxxxxxxxxxxxxxx>
Date: Mon, 20 Dec 2004 14:01:28 -0500
Sylvia, what is the problem?  You included the XML file and the XSL
style sheet, but you didn't say what the output looks like and how is it
wrong.

Did you intend to use the sort "number" with the "age" instead of the
"name"?

Hardy Merrill

>>> jneff@xxxxxxxxxxxxxxx 12/20/04 01:26PM >>>
>  <xsl:sort select="name" data-type="number"/>
						  ^^^^^^

Should that be number?

--Jim

 

-----Original Message-----
From: Sylvia Murphy [mailto:murphys@xxxxxxxx] 
Sent: Monday, December 20, 2004 1:23 PM
To: xsl mailing list
Subject: [xsl] xsl:sort not working under unix???

to demonstrate this behavior, I have created a simple test case.  Are
there
known unix issues or is the stupid newbie error. note the
transformation is
occuring in the browser (NN7).  


Thanks,

sylvia

simple xml file:

<?xml version="1.0"?>
<?xml-stylesheet type="text/xml" href="./sort.xsl"?> <addressbook>
<address>
   <name>Sylvia</name>
   <age>39</age>
   <state>CA</state>
 </address>

 <address>
   <name>Mariana</name>
   <age>90</age>
   <state>CO</state>
 </address>

</addressbook>


here is the style sheet:
<?xml version="1.0"?>

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>

  <xsl:template match="/">
    <html>
    <head></head>
    <body>
    <h1> TEST of SORT</h1>


    <xsl:for-each select="addressbook">
      <xsl:sort select="name" data-type="number"/>
      <xsl:apply-templates/>
    </xsl:for-each>
    </body>
    </html>

  </xsl:template>

  <xsl:template match="address">
    <p>
    <xsl:value-of select="age"/>
    <xsl:text> </xsl:text>
    <xsl:value-of select="name"/>
    <xsl:value-of select="$newline"/>
    </p>
  </xsl:template>


</xsl:stylesheet>

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