[xsl] xsl:sort now working under unix

gentlemen,

thanks for your replies. let me clarify.

I have played with the sort to sort by name under "text" mode and age under "number" mode. the code snippet I sent you was half-way between those two experiments.

the results of these tests is that I get no sorting at all. the groups are posted to the html in the order in which they exist in the xml file. this is a copy of the resulting html file

*********************************************************
TEST of SORT

should be listed in descending order by age (oldest to youngest)

30 Sylvia

39 Mariana

*********************************************************


here is the stylesheet with the corrected field to field type:
<?xml version="1.0"?>

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>

 <xsl:template match="/">
   <html>
   <head></head>
   <body>
   <h1> TEST of SORT</h1>
   <p>should be listed in descending order by age (oldest to youngest)</p>

   <xsl:for-each select="addressbook">
<!--descending or ascending (default) -->
     <xsl:sort select="age" data-type="number" order="descending"/>
     <xsl:apply-templates/>
   </xsl:for-each>
   </body>
   </html>

</xsl:template>

 <xsl:template match="address">
   <p>
   <xsl:value-of select="age"/>
   <xsl:text> </xsl:text>
   <xsl:value-of select="name"/>
   <xsl:value-of select="$newline"/>
   </p>
 </xsl:template>

</xsl:stylesheet>

I appreciate your help. would you mind replying directly to me as well as the list since I am diagest mode.

cheers,

sylvia

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