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Subject: RE: [xsl] XML/XSLT formatting problem From: "Chris Hicks" <chrish2000@xxxxxxxxxxxxxx> Date: Thu, 6 Jan 2005 21:46:28 +1100 |
I think I've solved my problem,
<xsl:apply-templates select="image[id =
$lastid]/following-sibling::image[count(. | key('idkey', id)[1])=1]"/>
Thanks for all the help.
Chris
> -----Original Message-----
> From: Chris Hicks [mailto:chrish2000@xxxxxxxxxxxxxx]
> Sent: Thursday, 6 January 2005 8:50 PM
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: RE: [xsl] XML/XSLT formatting problem
>
> Thanks Michael,
>
> This has further been complicated by the fact that I have
> image ID's in the result set that are repeated..in what is
> essentially a de-normalised structure
>
> Eg.
>
> <results lastid="9">
> <image>
> <id>37</id>
> <imagetitle>Fred</imagetitle>
> <imagelocation>fred.jpg</imagelocation>
> <imagesubject>Fred</imagesubject>
> </image>
> <image>
> <id>9</id>
> <imagetitle>Wilma</imagetitle>
> <imagelocation>wilma.jpg</imagelocation>
> <imagesubject>Wives</imagesubject>
> </image>
> <image>
> <id>9</id>
> <imagetitle>Wilma</imagetitle>
> <imagelocation>wilma.jpg</imagelocation>
> <imagesubject>Women</imagesubject>
> </image>
> <image>
> <id>9</id>
> <imagetitle>Wilma</imagetitle>
> <imagelocation>wilma.jpg</imagelocation>
> <imagesubject>Fred</imagesubject>
> </image>
> <image>
> <id>22</id>
> <imagetitle>Barney</imagetitle>
> <imagelocation>barney.jpg</imagelocation>
> <imagesubject>Bam Bam</imagesubject>
> </image>
> <image>
> <id>22</id>
> <imagetitle>Barney</imagetitle>
> <imagelocation>barney.jpg</imagelocation>
> <imagesubject>Betty</imagesubject>
> </image>
> <image>
> <id>24</id>
> <imagetitle>Dino</imagetitle>
> <imagelocation>dino.jpg</imagelocation>
> <imagesubject>Dino</imagesubject>
> </image>
> <image>
> <id>24</id>
> <imagetitle>Dino</imagetitle>
> <imagelocation>dino.jpg</imagelocation>
> <imagesubject>Fred</imagesubject>
> </image>
> </results>
>
> So what I have is a key on id at the top of my template:
>
> <xsl:key name="idkey" match="image" use="id"/> ..
>
> Then I want to output a line for each unique ID using:
>
> <xsl:for-each select="photographs::[count(. | key('idkey',
> id)[1])=1]"> ..
>
> Is there any way in the above line I can apply the
> restriction that the id must be in a sibling of the image
> with the @lastid so I only output items with id's of 22 and 24?
>
> Cheers,
>
> Chris
>
>
>
>
> > -----Original Message-----
> > From: Michael Kay [mailto:mike@xxxxxxxxxxxx]
> > Sent: Thursday, 6 January 2005 8:29 PM
> > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> > Subject: RE: [xsl] XML/XSLT formatting problem
> >
> >
> > <xsl:template match="results">
> >
> > <xsl:apply-templates
> > select="image[id=current()/@lastid]/following-sibling::*">
> > ...
> >
> > Michael Kay
> > http://www.saxonica.com/
> >
> > > -----Original Message-----
> > > From: Chris Hicks [mailto:chrish2000@xxxxxxxxxxxxxx]
> > > Sent: 06 January 2005 07:09
> > > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> > > Subject: [xsl] XML/XSLT formatting problem
> > >
> > > Hi,
> > >
> > > I have a problem where I need to start printing values from
> > a nodeset
> > > starting from a certain position in the set.
> > >
> > > My xml looks similar to this:
> > >
> > > <results lastid="9">
> > > <image>
> > > <id>37</id>
> > > <imagetitle>Fred</imagetitle>
> > > <imagelocation>fred.jpg</imagelocation>
> > > </image>
> > > <image>
> > > <id>22</id>
> > > <imagetitle>Barney</imagetitle>
> > > <imagelocation>barney.jpg</imagelocation>
> > > </image>
> > > <image>
> > > <id>9</id>
> > > <imagetitle>Wilma</imagetitle>
> > > <imagelocation>wilma.jpg</imagelocation>
> > > </image>
> > > <image>
> > > <id>12</id>
> > > <imagetitle>Dino</imagetitle>
> > > <imagelocation>dino.jpg</imagelocation>
> > > </image>
> > > <image>
> > > <id>1</id>
> > > <imagetitle>Bam Bam</imagetitle>
> > > <imagelocation>bambam.jpg</imagelocation>
> > > </image>
> > > </results>
> > >
> > > I need to check the "lastid" attribute in the result node
> > when looping
> > > through the nodeset in order to know when to start
> printing results
> > > (this represents the last id printed on the previous
> page). In the
> > > above example I want to start printing results starting
> > from id = 12.
> > >
> > > Any tips on where to begin would be appreciated.
> > >
> > > Cheers,
> > >
> > >
> > > Chris
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