RE: [xsl] mixed content nodes question

[cknell@xxxxxxxxxx]

<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
  <xsl:output method="xml" indent="yes" encoding="UTF-8" />
  <xsl:strip-space elements="*" />

  <xsl:template match="/">
     <xsl:apply-templates />
  </xsl:template>

  <xsl:template match="root">
     <root>
        <xsl:apply-templates />
     </root>
  </xsl:template>

  <xsl:template match="child">
     <xsl:apply-templates />
  </xsl:template>

  <xsl:template match="leaf">
     <xsl:variable name="digit">
        <xsl:if test="./dictionary"><xsl:value-of select="./dictionary" /></xsl:if>
     </xsl:variable>
     <xsl:variable name="frag">
        <xsl:choose>
           <xsl:when test="./dictionary/@lookup='3'">Foo</xsl:when>
           <xsl:when test="./dictionary/@lookup='4'">Bar</xsl:when>
           <xsl:otherwise></xsl:otherwise>
        </xsl:choose>
     </xsl:variable>
     <leaf><xsl:value-of select="substring(.,1,string-length(.)-2)" /> <xsl:value-of select="$frag" /> <xsl:value-of select="substring(.,string-length(.)-1,string-length(.))" /></leaf>
  </xsl:template>

</xsl:stylesheet>
--
Charles Knell
cknell@xxxxxxxxxx - email



-----Original Message-----
From:     Jeb Boniakowski <jeb@xxxxxxxxxxx>
Sent:     Fri, 7 Jan 2005 13:35:38 -0500
To:       xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject:  [xsl] mixed content nodes question

Hi--

I'm really new to XSL and I'm having trouble figuring out how to do 
what seem to be fairly basic things.  For example, say I have the 
following file:

<root>
 <child>
  <leaf>Leaf Value1</leaf>
  <leaf>Leaf Value2</leaf>
 </child>
 <child>
  <leaf>Leaf Value <dictionary lookup="3"/> 3</leaf>
 </child>
</root>

and I wanted to transform it very simply to:

<root>
 <child>
  <leaf>Leaf Value1</leaf>
  <leaf>Leaf Value2</leaf>
 </child>
 <child>
  <leaf>Leaf Value Foo 3</leaf>
 </child>
</root>

I'd imagine I'd have some part of my xsl sheet include a long 'when' 
block and switch on the lookup attribute's values so i'd have:
<xsl:when test="3">Foo</xsl:when>
<xsl:when test="4">Bar</xsl:when>

But I can't figure out how to do the actual transforming of only those 
<dictionary> tags in place, leaving the rest of the file unchanged.  
I've tried apply-templates in the a template matching "/", then having 
a template matching "*" do a test to see if the current node is 
<dictionary>, if so, transform and write out, otherwise, write out as 
it is, but I can't get it to work right.

If it's vastly easier to process if instead of having:
<dictionary lookup="3"/> -> Foo
I have:
<dictionary>3</dictionary> -> Foo

I might be able to make that change to the xml format, but I'm still 
confused about how to deal with mixed nodes.  I feel like people must 
do this all the time, if they have bits of HTML embedded in larger XML 
trees they must have markup tags like <b>, <a> that make the nodes 
mixed content, but I can't find a good example of it.

Also, I keep coming across vague references to the fact that MSXSL.exe 
v3 is perhaps not the ideal way of transforming my xml docs.  Given 
that I'm on windows, is there a better tool to use?

Any help or pointers to help would be greatly appreciated,
jeb.