[xsl] XPath syntax error problem

[Kenneth Stephen <marvin.the.cynical.robot@xxxxxxxxx>]

Hi,

    I have the following template in my XSL :

	<xsl:template match="xsd:element">
		<xsl:variable name="elementName" select="@name" />
		<xsl:if test="count(//*[substring-after(@ref,':') = $elementName] = 0">
			<xsl:if test="count(@name) = 1">
				<xsl:if test="/xsd:schema/@elementFormDefault = 'qualified'">
					<xsl:value-of select="concat($prefix,':')" />
				</xsl:if>
				<xsl:value-of select="@name" />
			</xsl:if>
		</xsl:if>
		<xsl:text>&eol;</xsl:text>
	</xsl:template>

    On execution, Saxon (and Xalan too) complain about a syntax error
on the outermost "xsl:if" . The Saxon error is shown below :

bash-2.05b$ java net.sf.saxon.Transform ../data/Metadata_0101.xsd
analyze-schema.xsl
Error at xsl:if on line 24 of
file:/C:/cygwin/home/zaphod/code/analyze-schema.xsl:
  XPath syntax error in {...(@ref,':') = $elementName] ...}:
    expected ")", found "<eof>"
Transformation failed: Failed to compile stylesheet. 1 error detected.


    What am I doing wrong? What I want to do is find out if the value
of the "name" attribute on an xsd:element in the input occurs within a
"ref" attribute elsewhere in my XML Schema file.

Thanks,
Kenneth