RE: [xsl] with-param problem

[Pieter Reint Siegers Kort <pieter.siegers@xxxxxxxxxxx>]

Hi Wim,

The variable p1 is not defined nor in scope here like others already
expained.

You can do however:

<xsl:template match="/a">
  <xsl:element name="S">
   <xsl:call-template name="f">
    <xsl:with-param name="p1" select="3"/>
   </xsl:call-template>
  </xsl:element>
</xsl:template>

<xsl:template name="f">
  <xsl:param name="p1"/>
  <xsl:param name="p2" select="$p1 + 2"/>
</xsl:template>

Here, the variable p1 is in scope and is defined, and will evaluate to the
value '5'.
However, if this would be of value to you, I don't know.

Cheers,
<prs/>

-----Original Message-----
From: Wim Janssen [mailto:Wim.Janssen@xxxxxxxxxxxxxxxxx] 
Sent: Thursday, February 03, 2005 12:46 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: [xsl] with-param problem

Hi,
 
I'm working on a master thesis about XSLT.
 
I found a problem and I don't know wether it is a bug in saxon (version
8.0).
 
Take a look a this little program
 
 <xsl:template match="/a">
  <xsl:element name="S"> 
   <xsl:call-template name="f">
    <xsl:with-param name="p1" select="3"/>
    <xsl:with-param name="p2" select="$p1 + 2"/>
   </xsl:call-template>
  </xsl:element>
 </xsl:template>
 
 <xsl:template name="f">
  <xsl:param name="p1"/>
  <xsl:param name="p2"/>
 </xsl:template>
 
The problem is the param named "p2".  It uses param "p1".  Why is that not
allowed in XSLT? Or is it maybe a bug in Saxon?
 
I'm sorry for my terrible English!
 
greetings
 
Wim Janssen