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Subject: [xsl] Can I use a boolean variable in an xsl:if test From: Ken Goodridge <goodridgehunting@xxxxxxxxx> Date: Tue, 8 Feb 2005 07:38:53 -0800 (PST)  | 
   I've been using the following xsl with success, but
I am seeing the xsl:if not work properly in another
installation. In both cases I get
<debug><show>false</show><time>60000</time></debug>,
but in one case the noshow shows. Does this code break
the rules or am I seeing a bug in the xsl transform?
In both cases I'm using xalan. I can check to see if
the versions are different if someone thinks that may
help.
<xsl:template name="my_template">
        <xsl:param name="time"/>
<!-- Don't show if time is one minute -->
<xsl:variable name="show">
  <xsl:value-of select = "$time != 60000" />
</xsl:variable>
<debug>
    <show><xsl:value-of select = "$show" /></show>
    <time><xsl:value-of select = "$time" /></time>
</debug>
<xsl:if test="$show">
    <noshow><xsl:value-of select = "$show" /></noshow>
</xsl:if>
</xsl:template>
		
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