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Subject: [xsl] Display children of node with given id!! From: "Adam J Knight" <adam@xxxxxxxxxxxxxxxxx> Date: Tue, 15 Feb 2005 20:04:56 +1000 |
Hi all,
I have had it. I don't have a clue.
I want to display all the children of node with id (ie: 7) should be: 8,9.
COMPLETE XML STRUCTURE:
<tree>
<tree_node id="7" value="Test">
<tree_node id="8" value="Test Sub"/>
<tree_node id="9" value="Test Sub One">
<tree_node id="10" value="Test Sub Two"/>
</tree_node>
</tree_node>
<tree_node id="11" value="Test 2"/>
</tree>
COMPLETE XSL STRUCTURE:
<?xml version="1.0"?>
<xsl:stylesheet version="1.1"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:param name="css"/>
<xsl:param name="url"/>
<xsl:param name="id"/>
<xsl:output method="html" indent="yes"/>
<xsl:template match="/">
<table cellspacing="0" cellpadding="2" class="{$css}">
<tr>
<td class="ui_tree_bar">
<a href="{$url}&action=add">add</a>
</td>
</tr>
<xsl:apply-templates/>
</table>
</xsl:template>
<xsl:template match="tree_node[parent::tree or
child::tree_node[@id=$id]]">
<tr>
<td>
<table width="100%">
<tr>
<td align="right" width="{count(ancestor-or-self::*) * 10}">
<a href="{$url}&node={@id}">+</a>
</td>
<td>
<xsl:value-of select="@value"/>
</td>
<td width="25%">
<a href="{$url}&action=edit&node={@id}">edit</a>
<a
href="{$url}&action=delete&node={@id}">delete</a>
</td>
</tr>
</table>
</td>
</tr>
<xsl:apply-templates/>
</xsl:template>
</xsl:stylesheet>
This stylesheet doesn't do it, appreciate any corrections.
Cheers,
Adam
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