Subject: Re: [xsl] Finding the position of node in foreign node list From: "Joris Gillis" <roac@xxxxxxxxxx> Date: Thu, 03 Mar 2005 21:53:09 +0100 |
Any ideas how I can find out what the position of the current node is in a
foreign node set? (As opposed to the position in the current node set)
regards, -- Joris Gillis (http://www.ticalc.org/cgi-bin/acct-view.cgi?userid=38041) Veni, vidi, wiki (http://www.wikipedia.org)
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