[xsl] XSLT 2.0 function - fastest node comparison

["Andrew Welch" <ajwelch@xxxxxxxxxxxxxxx>]

I'm checking if a number exists within a set of ranges.  The ranges are
stored as a variable:

<xsl:variable name="ranges">
  <range from="988" to="989"/>
  <range from="1008" to="1009"/>
  <range from="1014" to="1014"/>
  <range from="1025" to="1036"/>
  <range from="1038" to="1103"/>
  <range from="1105" to="1116"/>
  <range from="1118" to="1119"/>
  <range from="4150" to="4150"/>
  <range from="8194" to="8197"/>
  ...
</xsl:variable>

I've written a function that accepts an integer and returns true or
false if the number exists within one of the ranges:

<xsl:function name="f:isInRange" as="xs:boolean">
  <xsl:param name="char" as="xs:integer"/>
  <xsl:sequence select="if ($ranges/range[@from &lt;= $char][@to &gt;=
$char])
                        then true()
                        else false()"/>
</xsl:function>


-Is there a better way of writing this?

-How efficient is the test?  Does it check each <range> element
sequentially in document order?

thanks
andrew