[xsl] XSL:IF and Sort Results

[Jason Trépanier <jtrepanier@xxxxxxxxxxx>]

Im trying to display results based on a keyword which is working just fine.

The problem is that it shows the results found 3 times (the current total 
number of records),
besides that, everything is working nicely.

Code:

<?xml version="1.0" encoding="ISO-8859-1" ?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="html" encoding="ISO-8859-1" indent="yes"/>

        <xsl:param name="keyword">none</xsl:param>

<xsl:template match="/">

        <xsl:apply-templates/>

</xsl:template>

<xsl:template match="fiches/fiche">
        <xsl:for-each select="//fiche">
        <xsl:sort order="descending" select="texte/fichetitre"/>
        <xsl:if test="texte/*= $keyword">
        <table width="100%"  border="0" cellspacing="0" cellpadding="0">
        <tr>
                <td width="*" class="pad">
                        <xsl:value-of select="texte/fichetitre" />
                </td>
                <td width="150" align="center" class="pad"><xsl:value-of 
select="texte/typeheberg" /></td>
                <td width="150" align="center" class="pad"><xsl:text>temp 
text</xsl:text></td>
                <td width="100" align="center" class="pad"><xsl:value-of 
select="region/regionnseo" /></td>
        </tr>
        </table>
        </xsl:if>
        </xsl:for-each>
</xsl:template>

</xsl:stylesheet>

Anyone know how to fix this?


thank you in advance
J