RE: [xsl] question about filling of nodeset

Subject: RE: [xsl] question about filling of nodeset
From: "Armand Datema" <armand.datema@xxxxxxxxxxxxxxx>
Date: Thu, 17 Mar 2005 16:41:50 +0100

That's much better indeed, im not that much of an xsl programmer I code
most in .net.

What would be the best way to get a new result tree, any tutorials,
articles, sample code?



-----Original Message-----
From: David Carlisle [mailto:davidc@xxxxxxxxx]
Sent: Thursday, March 17, 2005 4:38 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: [xsl] question about filling of nodeset

  Now I have this code

  <xsl:variable name="AllKatern">
   <xsl:for-each select="/HowardsHome/Katern">

    <xsl:copy-of select="."/>
  <xsl:variable name="AllKaternNodes"

that's quite an expensive operation as you have to copy everthing and
also requires the node-set extension

 <xsl:variable name="AllKaternNodes" select="/HowardsHome/Katern"/>

Is a lot less to type and a _lot_ more efficient and just saves the node
set directly, which is almost certainly what you want here.

  Here I have a copy of everything but now I want the <title> of each
  Article with replaced quotes single double etc. That's not the
  but how can I write the result of this back to the nodeset?

You can never "write back" to anything in xslt, the transformation model
is always that you take a source tree and generate a new result tree.
So in your case you would apply som etemplates to $AllKaternNodes
and get a new tree, then do with it whatever you need to do
either letting it go to the main result tree, or saving it in a


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