[xsl] Select nodes with equal position

[Norbert Heidbrink <nh@xxxxxxxx>]

Hallo everyone,

depending on the postion() of a certain node I would like to select 
another node with the same position.
It works if I invent a variable.
But I wonder if there is a way to do it without the use of a variable?


XML:

<table>
  <colspec colname="c1"/>
  <colspec colname="c2"/>
  <colspec colname="c3"/>
  <row>
    <entry colname="c1">r1_1</entry>
    <entry colname="c2">r1_2</entry>
    <entry colname="c3">r1_2</entry>
  </row>
</table>


XSL:
<xsl:template match="entry">
  <xsl:variable name="mypos">
    <xsl:value-of select="position()"/>
  </xsl:variable>
  <xsl:value-of select="../../colspec[position() = $mypos]/@colname"/>
</xsl:template>


Best regards and thanks for your comments,
Norbert Heidbrink