Subject: [xsl] default namespace error in xalan From: omprakash.v@xxxxxxxxxxxxx Date: Wed, 20 Apr 2005 15:49:42 +0530 |
Hi, I have a stylesheet with a number of namespace declarations in the stylesheet element like so: <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0" xmlns:xalan="http://xml.apache.org/xalan" xmlns:xsd="schema ns" xmlns:prefix=" foo namespace" xmlns:acord-doc=" adoc namespace" xmlns:jag=" jag namespace" xmlns=" no namespace " exclude-result-prefixes="xalan" > <xsl:strip-space elements="*"/> <xsl:output method="xml" indent="yes" /> <xsl:template match="/"> <xsd:schema> </xsd:schema> </xsl:template> </xsl:stylesheet> However, the above stylesheet does not compile and throws the error "Could not locate the translet class "xamp" where xamp.xsl is the name of the stylesheet file. Iam using Xalan from the jar shipped with JAXP-1.3. The stylesheet works if I remove the line xmlns=" no namespace " from the "xsl:stylesheet" element. Cheers, Omprakash.V This e-Mail may contain proprietary and confidential information and is sent for the intended recipient(s) only. If by an addressing or transmission error this mail has been misdirected to you, you are requested to delete this mail immediately. You are also hereby notified that any use, any form of reproduction, dissemination, copying, disclosure, modification, distribution and/or publication of this e-mail message, contents or its attachment other than by its intended recipient/s is strictly prohibited. Visit Us at http://www.polaris.co.in
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