Re: [xsl] accessing different nodes when comparing two xml files

[David Carlisle <davidc@xxxxxxxxx>]

I have declared two variables that will contain the two document trees.

    <xsl:variable name="first">First.xml</xsl:variable>
    <xsl:variable name="second" select="document('Second.xml')/Top"/>

That $first does not contain a document it contains a result tree
fragment that corresponds to a document node that has (just) a text node
with value the string "First.xml".

presulamably you intended that to be
    <xsl:variable name="first" select="document('First.xml')/Top"/>

  <xsl:for-each  select="$first/f
Thus will give you a compile time error as $first is a result tree
fragment not a node set.

However your xpaths are not going to work I expect.

for example

  $second/following-sibling::SubConcepts

If Second.xml is a well formed XML file it has only one top level
element, presumably called Top. $second is bound to that element node
and so will have no following siblings, so this will be th eempty set.

David

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