RE: [xsl] org.apache.xpath.objects.XRTreeFrag error

["Aron Bock" <aronbock@xxxxxxxxxxx>]

Thorsten,

Whenever you do something like:

<xsl:variable>
 .. something other than a scalar value
</xsl:variable>

You end up with a "tree fragment", as you've found.  Such fragments need to 
be converted to a nodeset, which extension function is offered by various 
processors.  "node-set", by the MSXML processor, "nodeset" by xalan, etc.  
You should be able to find examples on the net.

As far as possible, however, try not to create a tree fragment (in XSLT 
1.0); it makes life easier.  In Your case you could define your variable as:

<xsl:variable name="objectProperty" select="..."/>

and you'd get back a node-set that could be simply traversed further 
downstream.

Regards,

--A


> From: Thorsten Scherler <thorsten@xxxxxxxxxx>
> Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] org.apache.xpath.objects.XRTreeFrag error
> Date: Fri, 06 May 2005 14:32:14 +0200
>
> Hi list,
>
> I am trying to process the following code:
>
> I defined a variable like:
> <xsl:variable name="objectProperty">
>  <xsl:copy-of select="$model[@objectId=
> $objectId]/forrest:property[@name=$name]"/>
> </xsl:variable>
>
> This variable $objectProperty is a frag like this:
>       <forrest:property newId="221" name="mq1-preis">
>         <euro>85</euro>
>         <cent>00</cent>
>       </forrest:property>
>
> Then I call another template with this frag:
> <xsl:call-template name="getText">
>   <xsl:with-param name="setX">
>    <xsl:copy-of select="$objectProperty"/>
>   </xsl:with-param>
> </xsl:call-template>
>
> In the final template I have
> <xsl:template name="getText">
>   <xsl:param name="setX"><test>This is a test.</test></xsl:param>
> ...
>   <xsl:copy-of select="$setX"/>
> ...
> </xsl:template>
>
> That is working fine because it will output:
>       <forrest:property newId="221" name="mq1-preis">
>         <euro>85</euro>
>         <cent>00</cent>
>       </forrest:property>
>
> ...but as soon I as I change the final template and use
> <xsl:value-of select="$setX/euro"/> or
> <xsl:copy-of select="$setX/euro"/>
>
> I get
> javax.xml.transform.TransformerException: java.lang.ClassCastException:
> org.apache.xpath.objects.XRTreeFrag
>
> Can anybody tell me what is going wrong and why the XPath is not
> working?
>
> TIA
>
> salu2
> --
> thorsten
>
> "Together we stand, divided we fall!"
> Hey you (Pink Floyd)

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