Re: [xsl] <xsl:sort>

[George Cristian Bina <george@xxxxxxx>]

Hi,

You select only one node (the current node that is a product element) 
and apply templates on it sorting this set (of one node) according with 
your criteria.

Something like below may behave as you expect:

<xsl:template match="document">
    <xsl:for-each select="child::node()">
        <!-- whatever processing you want to do -->
    </xsl:for-each>
    <xsl:apply-templates select="product">
        <xsl:sort select="category" data-type="number" order="descending"/>
    </xsl:apply-templates>
</xsl:template>

Best Regards,
George
---------------------------------------------------------------------
George Cristian Bina
<oXygen/> XML Editor, Schema Editor and XSLT Editor/Debugger
http://www.oxygenxml.com


aspsa wrote:
> Hi, folks.
>
> I have an XML document which structure is the following:
>
> <document>
>   <header>
>   <paragraph>
>   <subheader>
>   <paragraph>
>   .
>   .
>   .
>   <product>
>     <partname>
>     <category>
>     .
>     .
>     .
>   </product>
>   <product>
>     <partname>
>     <category>
>     .
>     .
>     .
>   </product>
>   .
>   .
>   .
> </document>
>
> In a template that matches on "document", I have the following:
>
> <xsl:template match="document">
>   <xsl:for-each select="child::node()">
>     // etc...
>   </xsl:for-each>
> </xsl:template>
>
> The XSLT stylesheet works fine, but now I need to sort the "product"
> elements based upon the "category" element and in descending order. The
> category content is numeric.
>
> How would I execute this from within the "document" template?
>
> Here's what I've tried.
>
> <xsl:template match="document">
>   <xsl:for-each select="child::node()">
>     <xsl:if test="product">
>       <xsl:apply-templates select=".">
>         <xsl:sort select="category" data-type="number" order="descending" />
>       </xsl:apply-templates>
>     </xsl:if>
>   </xsl:for-each>
> </xsl:template>
>
> Where am I going wrong? Thanks for your feedback.
>
>
> Respectfully,
>
> ASP