Subject: Re: [xsl] <xsl:output method="xml"> and an if sentence to output XML From: Jacob Friis Larsen <webcom.dk@xxxxxxxxx> Date: Mon, 9 May 2005 18:46:04 +0200 |
> I'd like to use <xsl:output method="xml">, but I haven't found a > solution to my problem, which is how to output <dd class="active"> if > parameter this exists and <dd> if it doesn't exist. > > <xsl:if test="@this"> > <xsl:attribute name="class">active</xsl:attribute> > </xsl:if> Great, thanks. > Also why do you have > > <xsl:for-each select="/opml/body/outline"> > <xsl:call-template name="outline"> > ... > <xsl:template name="outline"> > > Rather than the simpler and more natural > > <xsl:apply-templates select="/opml/body/outline"/> > ... > <xsl:template match="outline"> True. This is my new syntax: <xsl:template match="/opml/body/outline"> ... > If you are outputting html don't you want to use the html output method > rather than xml? (You certainly don't want to use the text output > method) If I use html I get a <!DOCTYPE ...> in the output although I have standalone="no". The output is inserted in a XHTML file, so I guess XML is fine? Thanks for your help. Jacob
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