RE: [xsl] Convert html:br to paragraphs

Gregor,

If all elements are children of <body>, the following will work. On your input:

<body>1. para is here <br/>
2. para is here and <b>bold</b> or another
inline element </body>

This XSL (inspired by http://www.biglist.com/lists/xsl-list/archives/200505/msg00146.html, which I've since learned is a fairly well-known technique):

<?xml version="1.0" encoding="iso8859-1"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";> <xsl:output method="xml" indent="yes"/>

   <xsl:template match="body">
       <xsl:copy>
           <xsl:call-template name="wrap">
               <xsl:with-param name="n" select="node()[1]"/>
           </xsl:call-template>
       </xsl:copy>
   </xsl:template>

<xsl:template name="wrap"> <xsl:param name="n" select="/.."/> <xsl:param name="a" select="/.."/> <xsl:choose> <xsl:when test="$n[self::br]"> <xsl:copy-of select="$a"/> <xsl:call-template name="wrap"> <xsl:with-param name="n" select="$n/following-sibling::node()[1]"/> </xsl:call-template> </xsl:when> <xsl:when test="$n"> <xsl:call-template name="wrap"> <xsl:with-param name="n" select="$n/following-sibling::node()[1]"/> <xsl:with-param name="a" select="$a|$n"/> </xsl:call-template> </xsl:when> <xsl:otherwise> <xsl:copy-of select="$a"/> </xsl:otherwise> </xsl:choose> </xsl:template>

</xsl:stylesheet>

produces:

<?xml version="1.0" encoding="UTF-8"?>
<body>
 <p>1. para is here </p>
 <p>
2. para is here and <b>bold</b> or another
inline element </p>
</body>

If elements could occur at any depth ... see this thread: http://www.biglist.com/lists/xsl-list/archives/200505/msg01413.html

Regards,

--A

i have to convert <br/> structured html sites into documents with a
paragraph structure.

that means:

<body>1. para is here <br/>
2. para is here and <b>bold</b> or another
inline element </body>

has to be:

<p>1. para is here</p>
<p>2. para is here and <b>bold</b> or another
inline element</p>

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