Subject: Re: [xsl] How to select either ElementA -OR- ElementB in an axis From: Eric van der Vlist <vdv@xxxxxxxxxxxx> Date: Wed, 15 Jun 2005 21:38:13 +0200 |
Hi, On mer, 2005-06-15 at 12:25 -0700, Christopher R. Maden wrote: > chris wrote: > > Thanks for the response. Are you sure that's correct or am I goofing > > it up somehow? Using Saxon 8.4, I get an error trying to use your > > solution... > > No, that won't work. You need to look at all your ancestors, then find > the closest one that matches your pattern: > > ancestor::*[name() = 'A' or name() = 'B'][1] Using name() = 'A' is not namespace safe and self::A should be preferred in such situations : ancestor::*[self::ElementA | self::ElementB][1] Also note that the order of the ancestor axis can be misleading since you'll get the first one starting from the context node going toward the document root. Eric > > HTH, > Chris -- Curious about Relax NG? Read my book online. http://books.xmlschemata.org/relaxng/ ------------------------------------------------------------------------ Eric van der Vlist http://xmlfr.org http://dyomedea.com (ISO) RELAX NG ISBN:0-596-00421-4 http://oreilly.com/catalog/relax (W3C) XML Schema ISBN:0-596-00252-1 http://oreilly.com/catalog/xmlschema ------------------------------------------------------------------------
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