Subject: [xsl] (SOLVED) Re: [xsl] xsl != not working? From: Joe Stump <joe@xxxxxxxxxxxx> Date: Tue, 21 Jun 2005 10:59:50 -0700 |
I've got a bunch of h2's in a document that I want to group at the top with jumps to the actual h2's in the body, which I have working without incident. The problem I have is with links back to the top. Basically, if it's NOT the first h2, it should show a "Back to Top" link above the h2. I have a test that appears to be exactly what I need, but it's not working. The basic test is:
//h2[1]/text() != text()
Below is the full XSLT (it's in a template matching h2's).
<xsl:if test="//h2[1]/text() != text()"> <xsl:text>"</xsl:text> <xsl:value-of select="//h2[1]/text()"/> <xsl:text>"</xsl:text> <xsl:text> != </xsl:text> <xsl:text>"</xsl:text> <xsl:value-of select="text()"/> <xsl:text>"</xsl:text>
<xsl:element name="div"> <xsl:attribute name="class">article-top</xsl:attribute> <xsl:element name="a"> <xsl:attribute name="class">article-top</xsl:attribute> <xsl:attribute name="href">#top</xsl:attribute> <xsl:text>Back to Top</xsl:text> </xsl:element> </xsl:element> </xsl:if>
Here's my output for my first h2 (which should NOT have a link to top above it):
"Definition" != "Definition" Back to Top
Quite annoying ... any ideas? How can 'Definition' not equal 'Definition'?
--Joe
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