Re: [xsl] Counting preceding nodes

[Wendell Piez <wapiez@xxxxxxxxxxxxxxxx>]

Billie,

At 01:29 PM 6/24/2005, you wrote:
> I gave the diagrams the appropriate names so you could see what I was 
> looking for, but basically,
> I'm looking for a way to number the diagrams based on the absolute order 
> in which they are placed.

This statement of the problem suggests it might be handled with the 
xsl:number instruction, which is designed to do this.

You might want <xsl:number level="any"/>. A good XSLT reference will help.

> I've tried all sorts of combinations but nothing seemed to work.  One 
> logical structure I came up
> with, that I couldn't figure out how to translate into XSL, was: "count 
> the number of diagrams that
> have an ancestor-or-self which is a preceding-sibling to an 
> ancestor-or-self of the diagram in
> question".  Is that possible to do?

Yes (sort of), but there are also easier ways, such as using 
"count(preceding::diagram)". You don't need to worry about counting 
ancestors unless diagrams are allowed to contain other diagrams.

But xsl:number is the thing to use unless there's some reason not to.

Cheers,
Wendell


======================================================================
Wendell Piez                            mailto:wapiez@xxxxxxxxxxxxxxxx
Mulberry Technologies, Inc.                http://www.mulberrytech.com
17 West Jefferson Street                    Direct Phone: 301/315-9635
Suite 207                                          Phone: 301/315-9631
Rockville, MD  20850                                 Fax: 301/315-8285
----------------------------------------------------------------------
  Mulberry Technologies: A Consultancy Specializing in SGML and XML
======================================================================