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Subject: [xsl] Sum of identical nodes From: Alvin Ng <ngkwangming@xxxxxxxxx> Date: Wed, 20 Jul 2005 14:18:34 +0800  | 
Hi,
Sorry for this repost... but I needed some help with this. Any help is
greatly appreciated. Below is an example of what I hope to acheive
In this example, my input files are File1 and File2 and wish to output
my result to File3
- add 1 from File1/AAA to 2 from File2/AAA to output File3
- add 2 from File1/AAA to 3 from File2/AAA to output File3
- add 2 from File1/BBB to 0 from File2/BBB to output File3
- add 3 from File1/BBB to 0 from File2/BBB to output File3
Each file in File1 and File2 have few hundreds nodes of <moid></moid>
and <mt></mt>. My biggest hindrance is how to recursively sum up each
node from each nodeset.
File 1:
<xml>
<moid> AAA </moid>
    <mt> 1 </mt>
    <mt> 2 </mt>
<moid> BBB </moid>
    <mt> 2 </mt>
    <mt> 3 </mt>
</xml>
File 2:
<xml>
<moid> AAA </moid>
    <mt> 2 </mt>
    <mt> 3 </mt>
<moid> BBB </moid>
    <mt> 0 </mt>
    <mt> 0 </mt>
</xml>
File 3:
<xml>
<moid> AAA </moid>
    <mt> 3 </mt>
    <mt> 5 </mt>
<moid> BBB </moid>
    <mt> 2 </mt>
    <mt> 3 </mt>
</xml>
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