Subject: Re: [xsl] Generating table cells and rows From: David Carlisle <davidc@xxxxxxxxx> Date: Mon, 1 Aug 2005 11:34:09 +0100 |
> I would like to know if there is a way to do this with a table? Is it > possible to output 5 table cells and add another <tr> tag if required Don't think in terms of tags, XSLT can not process tags. You want to generate a row every 5 nodes, and within that row process the current node and its four next siblings: <xsl:template name="displayPhotos"> <xsl:for-each select="$currentNodes[position() mod 5 = 1"> <tr> <xsl:for-each select=".|following-sibling::*[position()<4]"> <img src="{$photo_server}/?studentId={id}"/><br /> Name: <xsl:value-of select="name"/> </xsl:for-each> </tr> </xsl:for-each> </xsl:template> ________________________________________________________________________ This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________
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