RE: [xsl] XSLT 2.0 matches function (Saxon)

["Michael Kay" <mike@xxxxxxxxxxxx>]

> I thought I was making some stupid mistake evident to anyone but me.

Well, if you can't spot the error with the diagnostics in front of you, then
it's unlikely other people will be able to spot it without...
 
> Here's the err msg:
> 
> Error at xsl:value-of on line 18 of 
> file:/F:/Dane/tymczas/xliff/saxon/segment.xsl:
>    FORX0002: net.sf.saxon.type.RegexTranslator$RegexSyntaxException: 
> Error at character 2 in regular expression: bad escape sequence

Good, that immediately eliminates lots of possibilities.
> 
> I got no error on using quotes around $before but then I got "false" 
> everytime in the output as nothing matched (and it should, given the 
> contents of beforebreak).

You mean you tried matches(...., '$before')? That would match any string
that contains the characters "before" after the end of the string....

> 
> > You haven't given any evidence that the 
> select="beforebreak" is actually
> > selecting the element you've shown.
> 
> I checked that with a template:
> 
> <xsl:template match="//rule[@break='yes']">
>    <xsl:variable name="before" select="beforebreak"/>
>    <xsl:value-of select="$before"/>
>    <!-- xsl:value-of select='matches($segmented_file//Raw, 
> $before)'/ -->
>      <xsl:apply-templates/>
>    </xsl:template>
> 
> 
> And I got the content of it in the output (I've five <rule> elements, 
> and three of them have beforebreak filled in, so it got concatenated):
> 
> <?xml version="1.0" 
> encoding="UTF-8"?>[\.\?!]+[\.\?!]+[\xff61\x3002\xff0e\xff1f\xff01]+
> 
> Does this sound like evidence?
> 

Absolutely. You said that $before contained "[\.\?!]+" and this shows that
it doesn't. There's some garbage in here, you need to find out where it came
from. \xff61 is not valid in an XPath regular expression.

Michael Kay
http://www.saxonica.com/